Write C++ programs to implement the Kruskal’s algorithm to generate a minimum cost spanning tree
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/* Write C++ programs to implement the Kruskal’s algorithm to generate a minimum cost spanning tree */
#include
#include
#include
using namespace std;
int cost[10][10],i,j,k,n,m,c,visit,visited[10],l,v,count,count1,vst,p;
main()
{
int dup1,dup2;
cout<<"enter no of vertices";
cin >> n;
cout <<"enter no of edges";
cin >>m;
cout <<"EDGE Cost";
for(k=1;k<=m;k++)
{
cin >>i >>j >>c;
cost[i][j]=c;
cost[j][i]=c;
}
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
if(cost[i][j]==0)
cost[i][j]=31999;
visit=1;
while(visit
{
v=31999;
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
if(cost[i][j]!=31999 && cost[i][j]
{
int count =0;
for(p=1;p<=n;p++)
{
if(visited[p]==i || visited[p]==j)
count++;
}
if(count >= 2)
{
for(p=1;p<=n;p++)
if(cost[i][p]!=31999 && p!=j)
dup1=p;
for(p=1;p<=n;p++)
if(cost[j][p]!=31999 && p!=i)
dup2=p;
if(cost[dup1][dup2]==-1)
continue;
}
l=i;
k=j;
v=cost[i][j];
}
cout <<"edge from " <<<"-->"<
cost[l][k]=-1;
cost[k][l]=-1;
visit++;
int count=0;
count1=0;
for(i=1;i<=n;i++)
{
if(visited[i]==l)
count++;
if(visited[i]==k)
count1++;
}
if(count==0)
visited[++vst]=l;
if(count1==0)
visited[++vst]=k;
}
}
OUTPUT
enter no of vertices4
enter no of edges4
EDGE Cost
1 2 1
2 3 2
3 4 3
1 3 3
edge from 1-->2edge from 2-->3edge from 1-->3
This post was written by: Rajendra Prasad
Rajendra Prasad is a professional blogger, web designer and front end web developer. Follow him on Facebook
